2025年4月深圳市多校初三第二次适应性联合测试物理试卷答案

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2026-02-05 16:16 | 0 | 0 | 页数: 2 | 大小: 194 KB

2 0 2 5 4 ( 6 2 1 2 4 ) 1 5 1 6 1 7 1 8 1 9 2 0 A B A B D C ( 1 0 5 1 ) 2 1 . 2 线 0 . 5 0 . 5 2 2 . 2 2 1 3 2 3 . 2 5 0 0 2 5 0 2 4 . 3 N 2 5 . 4 1 0 . 1 0 0 . 1 2 1 4 5 3 4 2 6 . 7 1 0 . 2 2 1 0 3 e 4 0 . 6 2 7 . 7 1 N 1 0 6 k g / N 1 0 k g 1 0 6 0 0 0 7 3 × = × × = = m g G 2 N 1 0 6 7 × = = G F 0 . 5 2 J 1 0 2 4 . 3 m 1 0 5 4 N 1 0 6 1 0 3 5 × = × × × = = F s W 2 W 1 0 3 3 6 0 0 s 3 J 1 0 2 4 . 3 6 1 0 × = × × = = t W P 1 3 h k W 1 0 2 . 4 2 h k W 1 0 1 1 % 2 2 η 4 4 × = × × = = W W 1 3 0 2 5 h / 8 k W h k W 1 0 4 2 . 2 4 = × = n 0 . 5 3 0 2 5 h 8 k W h k W 1 0 4 2 . 2 4 = × = n
1/2
2 8 . 7 1 h / k m 1 8 0 h 6 0 1 0 k m 3 0 = = = t s v 2 s / m 5 0 6 0 s 1 0 m 1 0 3 0 3 = × × = = t s v 2 2 1 1 2 R R R R U P = 0 . 5 Ω = = = 2 W 7 2 V 1 2 2 2 1 P U R 2 W 2 4 4 2 V 1 2 2 2 = Ω + Ω = = R U P 1 3 A 2 4 2 V 1 2 = Ω + Ω = = R U I 1 V 8 4 A 2 2 2 = Ω × = = I R U 0 . 5 2 9 . 4 1 2 3 4 7 . 2 3 0 . 1 3 1 D 2 / / 3 S m g γ 4 5 . 5 × 1 0 5 8 3 . 3 2 0 5 1 3 2 0 ~ 3 0 6 2 2 1 R 0 1 3 0 Ω R 0
2/2
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